Given a sprinkler protection area of 130 square feet and a density of 0.25 gpm per square foot, what is the minimum sprinkler discharge?

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Multiple Choice

Given a sprinkler protection area of 130 square feet and a density of 0.25 gpm per square foot, what is the minimum sprinkler discharge?

Explanation:
To determine the minimum sprinkler discharge, you need to calculate the total water flow required based on the area protected and the density of water application. In this case, the sprinkler protection area is 130 square feet, and the density is 0.25 gallons per minute (gpm) per square foot. To find the total discharge, multiply the area by the density: Total discharge = Area × Density Total discharge = 130 sq ft × 0.25 gpm/sq ft Total discharge = 32.5 gpm So the minimum sprinkler discharge required to adequately protect the given area is 32.5 gpm. This calculation shows the direct relationship between the area being protected and the density of water required to ensure effective sprinkler performance. Thus, the answer of 32.50 gpm accurately represents the necessary flow rate based on the specific area and density parameters provided.

To determine the minimum sprinkler discharge, you need to calculate the total water flow required based on the area protected and the density of water application.

In this case, the sprinkler protection area is 130 square feet, and the density is 0.25 gallons per minute (gpm) per square foot. To find the total discharge, multiply the area by the density:

Total discharge = Area × Density

Total discharge = 130 sq ft × 0.25 gpm/sq ft

Total discharge = 32.5 gpm

So the minimum sprinkler discharge required to adequately protect the given area is 32.5 gpm. This calculation shows the direct relationship between the area being protected and the density of water required to ensure effective sprinkler performance.

Thus, the answer of 32.50 gpm accurately represents the necessary flow rate based on the specific area and density parameters provided.

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